Posted by Anonymous on .
a collapsible plastic bag contains a gluccose solution. If the average gauge pressure in the atery is 1.33x10^4Pa, what must be the minimum height h, of the bag in order to infuse gluccose into the artery? Assume that the specific gravity of the solution is 1.02.
(1.02)(1.33x10^4)=(1x10^3kg/m^3)(9.8)(h)
h=1.38 (I don't know how to get the answer in the back of the book, 1.33m)

physics 
bobpursley,
the specific gravity should be on the mass side (right side) of the equation.

physics 
Alan,
Gauge Pressure(P) = Density(p) x gravity(g) x height(h)
1.33x10^4Pa = 1.02* x 9.8m/s x h
*: Specific gravity = ratio of density of solution to water .:. Density = 1.02(no units)
.:. h = 1.33x10^4 / 1.02 x 9.8
= 1330.5m^3
= 1.33m