Saturday

April 19, 2014

April 19, 2014

Posted by **Anonymous** on Sunday, December 16, 2007 at 6:22pm.

(1.02)(1.33x10^4)=(1x10^3kg/m^3)(9.8)(h)

h=1.38 (I don't know how to get the answer in the back of the book, 1.33m)

- physics -
**bobpursley**, Sunday, December 16, 2007 at 7:09pmthe specific gravity should be on the mass side (right side) of the equation.

- physics -
**Alan**, Sunday, September 9, 2012 at 7:44amGauge Pressure(P) = Density(p) x gravity(g) x height(h)

1.33x10^4Pa = 1.02* x 9.8m/s x h

*: Specific gravity = ratio of density of solution to water .:. Density = 1.02(no units)

.:. h = 1.33x10^4 / 1.02 x 9.8

= 1330.5m^3

= 1.33m

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