Monday

March 2, 2015

March 2, 2015

Posted by **Anonymous** on Saturday, December 15, 2007 at 11:41pm.

for y=x^2, x=0, and y=0

(a) integral (x^2)^2 from 0 to 2=32/5

(b) integral 1/2 pi (1/2x^2)^2 from 0 to 2 = 4pi/5

(c) integral 1/2x^2(1/2)(x^2)(sqrt(3)) from 0 to 2 = 8(sqrt(3))/5

for y=sqrt(x), x=0, x=16, and y=0

(a) integral (sqrt(x))^2 from 0 to 16= 128

(b) integral 1/2pi[(1/2)(sqrtx)]^2 from 0 to 16 = 16 pi

(c) integral 1/2 (sqrtx)(1/2)(sqrt(x))(sqrt(3))=32sqrt(3)

for y=8-x^2, y=x^2

(a) integral (8-2x)^2 from -2 to 2 = 192

(b) integral 1/2 pi [(8-2x^2)/2]^2 from -2 to 2 =256pi/15

(c) integral (8-2x^2)(sqrt3)(4-x^2) from -2 to 2 = 1024(sqrt3)/15

**Answer this Question**

**Related Questions**

calculus - the region bounded by the quarter circle (x^2) + (y^2) =1. Find the ...

calculus - Find the volume of the solid whose base is the region bounded between...

Calculus - Find the volume of the solid whose base is the region in the xy-plane...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - Find the volume of the solid whose base is the region bounded by y=x^...

calculus - find the volume of the solid whose base is bounded by the graphs of y...

Calculus - The functions f and g are given by f(x)=√x and g(x)=6-x. Let R ...

math - find the volume of the solid whose base is bounded by y=e^(-x), y=3cos(x...