Posted by **jonathan** on Saturday, December 15, 2007 at 8:36pm.

There are 9 more quarter then dimes.if the total value of the coins is 6.8, how ,any quarters are there?

- math -
**drwls**, Saturday, December 15, 2007 at 8:58pm
Is the total value $6.80?

If so, then let Q be the number of quarters and D be the number of dimes.

You know that

Q -D = 9, and

0.25Q + 0.1D = 6.80

Solving bu substitution,

0.25Q + 0.1(Q-9) = 6.80

0.35Q = 7.70

Q = 22

Now solve for D

- math -
**jonathan**, Saturday, December 15, 2007 at 9:01pm
omg ty u are a super pro

- math -
**drwls**, Saturday, December 15, 2007 at 11:19pm
ty, yw :)

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