Someone has already posted this question, but their's was never answered, so hopefully someone can answer this. Thanks. An interference pattern is set up by two point sources of the same frequency, vibrating in phase with one another. A point on the second nodal line is 50.0 cm from one source and 59 cm from the other. The speed of the waves is 35 cm/s. Calculate the frequency of the sources. I know you do path difference (like Pms-Pms) and then do the universal wave equation.

Question

Someone has already posted this question, but their's was never answered, so hopefully someone can answer this. Thanks. An interference pattern is set up by two point sources of the same frequency, vibrating in phase with one another. A point on the second nodal line is 50.0 cm from one source and 59 cm from the other. The speed of the waves is 35 cm/s. Calculate the frequency of the sources. I know you do path difference (like Pms-Pms) and then do the universal wave equation.

Answer 1

Look for the answer I posted to the original question.

Answer 2

If there is a node (minimum) then the path difference is a multiple of odd 1/2 Lambda.

(n+ 1/2 )lambda= .09 meters

Now the first nodal line will be n=0, the second at n=1. Check my thinking

Now you have lambda, and the wave equation will give frequency.

freq*lambda= speed of waves.

Answer 3

Thanks for the help!

Answer 4

To calculate the frequency of the sources, we need to use the formula for the path difference and the equation relating wave speed, wavelength, and frequency.

1. Begin by determining the path difference. In the given problem, the point on the second nodal line is 50.0 cm from one source and 59 cm from the other. The path difference (Δx) can be calculated as the absolute difference between the two distances: Δx = |59 cm - 50.0 cm|.

2. Next, we can use the universal wave equation to relate wave speed, wavelength, and frequency. The equation is given as: v = λ * f, where v is the wave speed, λ (lambda) is the wavelength, and f is the frequency.

3. Rearrange the equation to solve for the wavelength (λ): λ = v / f.

4. Since the two sources have the same frequency, we can assume that they have the same wavelength. Therefore, the wavelength will be constant.

5. Now, substitute the formula for the wavelength into the path difference equation: Δx = λ.

6. We can now equate Δx (path difference) to λ (wavelength): Δx = v / f.

7. Rearrange the equation to solve for the frequency (f): f = v / Δx.

8. Plug in the given values to calculate the frequency: f = 35 cm/s / Δx.

9. Substitute the value of Δx obtained from step 1 into the equation and calculate the frequency.

By following these steps, you will be able to calculate the frequency of the sources based on the given information.