Posted by **Needs Physics help desperately** on Saturday, December 15, 2007 at 12:40pm.

Someone has already posted this question, but their's was never answered, so hopefully someone can answer this. Thanks. An interference pattern is set up by two point sources of the same frequency, vibrating in phase with one another. A point on the second nodal line is 50.0 cm from one source and 59 cm from the other. The speed of the waves is 35 cm/s. Calculate the frequency of the sources. I know you do path difference (like Pms-Pms) and then do the universal wave equation.

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**drwls**, Saturday, December 15, 2007 at 1:05pm
Look for the answer I posted to the original question.

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**bobpursley**, Saturday, December 15, 2007 at 1:08pm
If there is a node (minimum) then the path difference is a multiple of odd 1/2 Lambda.

(n+ 1/2 )lambda= .09 meters

Now the first nodal line will be n=0, the second at n=1. Check my thinking

Now you have lambda, and the wave equation will give frequency.

freq*lambda= speed of waves.

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**Needs Physics help desperately**, Saturday, December 15, 2007 at 1:12pm
Thanks for the help!

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