Posted by **Mary** on Friday, December 14, 2007 at 2:18am.

A charge of -3.00 µC is fixed at the center of a compass. Two additional charges are fixed on the circle of the compass (radius = 0.125 m). The charges on the circle are -4.60 µC at the position due north and +5.00 µC at the position due east. What is the magnitude and direction of the net electrostatic force acting on the charge at the center? Specify the direction relative to due east (0°).

Magnitude

_____N

Direction

______°

Magnitude:

(8.99e9)(4.6e-6)(3.0e-6)/ (0.125)^2

=7.94 N

(8.99e9)(5.0e-6)(3.0e-6)/ (0.125)^2

=8.63 N

Adding both values as vectors:

sqrt[(7.94N squared)+(8.63N squared)]

Magnitude= 11.73 N

Direction:

theta = inverse tan (7.94/8.63)

= 42.62 degrees South of East

- Physics please check -
**drwls**, Friday, December 14, 2007 at 6:53am
LOOks good to me!

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