Friday

November 21, 2014

November 21, 2014

Posted by **sam** on Friday, December 14, 2007 at 12:00am.

- science -
**DrBob222**, Friday, December 14, 2007 at 12:27am1 H = 1 x 1e each = 1 electron.

1 C = 1 x 4e each = 4 electrons.

1 N = 1 x 5e each = 5 electrons.

total = 10 electrons.

How many do we need? We need 8 for C, 8 for N, and 2 for H; therefore, we need our 10 electrons to do the job of 18 electrons. The difference is 18-10 = 8 and if we have electrons paired that is 8/2 = 4 bonds.**H:C:::N:**This gives us 4 bonds, C has 4 (which is usual), H has 1 (which is usual), N has 3 (which is usual), and we have used 10 electrons. Furthermore, we have two electrons around H, 8 around C and 8 around N. Have you learned how to do the formal charge. That is zero on H, zero on C, and zero on N.

**Answer this Question**

**Related Questions**

chemistry - help needed to draw lewis structures of hydrogen cyanaide(HCN) and ...

Chemistry - Can you tell me if i did these right?? Lewis Dot Structure A. BrF = ...

chemistry - I have to draw Lewis structures for hydrogen cyanide and cyanogen ...

science - NO2 ( negative by the 2 on the right side) how do I do this as lewis ...

Chem - Concerning compounds cyanogen, Hydrogen cyanide and sodium cyanide. ...

CHEM - the number of nonbonding electrons exceeds the number of bonding ...

physics - is this the strutual formula for hydrogen cyanide H:C:::N and is this ...

Chemistry - What is the Lewis dot structure for LiF? Is it Li - F with 2 dots on...

chemistry - What is the pH of a 1.24 mol/L solution of HCN(aq) if its Ka = 6.2 x...

Chemistry - For a lab experiment we have to draw the lewis structures of ...