1. calcium carbonate < calcium oxide + carbon dioxide

dr. Bob

Hydrolic acide + sodium hydroxide < sodium chloride + water

this cant be balanced already as assignment says we must balance each one

CaCO3 ==> CaO + CO2

already balanced.

HCl + NaOH ==> NaCl + H2O
already balanced.

Your arrow is pointing the wrong way, I assume. If not, then reverse the equations I wrote. ALSO, the equations are balanced without adding coefficients other than 1 to each reactant and each product. So if you must place a coefficient for each, place a 1.

You are right the arrow on the 2 is the wrong way so I am so confused as to how to balance these 2 they are the last problems I have.

What do you not understand about the balancing? These are relatively easy ones to do. If you don't understand these, a more complicated one will give you real trouble. I can go through one to show you how to do it. It's just trial and error. But it helps to use a little logic with it.

To balance a chemical equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation step by step:

1. Calcium Carbonate < Calcium Oxide + Carbon Dioxide

To balance this equation, we need to determine how many atoms of each element are on each side.

On the left side of the equation, we have one Calcium (Ca), one Carbon (C), and three Oxygen (O) atoms.

On the right side of the equation, we have one Calcium (Ca), one Carbon (C), and a total of four Oxygen (O) atoms (one from the Calcium Oxide and three from the Carbon Dioxide).

To balance the equation, we need to add a coefficient (a number in front of the chemical formula) to balance the atoms. In this case, we need to add a coefficient of 2 in front of Calcium Carbonate:

2CaCO3 < 2CaO + 2CO2

Now, the equation is balanced with two Calcium, two Carbon, and six Oxygen atoms on both sides.

2. Hydrochloric Acid + Sodium Hydroxide < Sodium Chloride + Water

Similarly, let's analyze the atoms on each side of the equation.

On the left side, we have one Hydrogen (H), one Chlorine (Cl), one Sodium (Na), and one Oxygen (O) atom.

On the right side, we have one Sodium (Na), one Chlorine (Cl), and two Hydrogen (H) and Oxygen (O) atoms from the water molecule.

To balance the equation, we can add a coefficient of 2 in front of Hydrochloric Acid:

2HCl + Sodium Hydroxide < Sodium Chloride + Water

Now, the equation is balanced with two Hydrogen, two Chlorine, one Sodium, and two Oxygen atoms on both sides.

Always remember to adjust the coefficients and not the subscripts within a chemical formula when balancing an equation.