Sunday

March 1, 2015

March 1, 2015

Posted by **Anonymous** on Thursday, December 13, 2007 at 6:39pm.

2^(5x-6) = 7

My work:

log^(5x-6) = log7

5x - 6(log2) = log7

5x = log7 + 6(log2)

x = (log7 + log2^6) / 5

And textbook answer:

(log7) / (log2)

What did I do wrong?

- Math - Logarithmic -
**Reiny**, Thursday, December 13, 2007 at 6:57pmyou are wrong and the textbook answer, the way you stated is, is wrong.

2^(5x-6) = 7

log[2^(5x-6)] = log7

(5x-6)log2 = log7

5x-6 = log7/log2

5x = log7/log2 + 6

x = (log7/log2 + 6)/5

**Answer this Question**

**Related Questions**

Math - Expand each logarithm. log 7(3x-2)^2 log(3xyz)^2 Thanks in advance. One. ...

math - Log7x=log7 4+log7 3 please help I can not anderstand thanks

Math - these are some problems i do not get any help is appreciated. These are ...

Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...

math - Solve for x in the following equations. (4 marks) log3(x - 5) + log3(x + ...

math - solve the equation log2(x+4)-log4x=2 the 2 and 4 are lower than the g ...

Math - The problem I have to solve is log with base 2 ^6 multiply by log base 6...

math30 - 1.Use the laws of logarithms to express log2 (6) – log2 (3) + 2log2 (...

Algebra - Solve the logarithmic equation. log2(4x)-log2(x+3)=1

algebra 2 - log 5 5 log7 (1/49)