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March 31, 2015

March 31, 2015

Posted by **Anonymous** on Thursday, December 13, 2007 at 6:39pm.

2^(5x-6) = 7

My work:

log^(5x-6) = log7

5x - 6(log2) = log7

5x = log7 + 6(log2)

x = (log7 + log2^6) / 5

And textbook answer:

(log7) / (log2)

What did I do wrong?

- Math - Logarithmic -
**Reiny**, Thursday, December 13, 2007 at 6:57pmyou are wrong and the textbook answer, the way you stated is, is wrong.

2^(5x-6) = 7

log[2^(5x-6)] = log7

(5x-6)log2 = log7

5x-6 = log7/log2

5x = log7/log2 + 6

x = (log7/log2 + 6)/5

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