Posted by Anonymous on Thursday, December 13, 2007 at 6:39pm.
Solve:
2^(5x6) = 7
My work:
log^(5x6) = log7
5x  6(log2) = log7
5x = log7 + 6(log2)
x = (log7 + log2^6) / 5
And textbook answer:
(log7) / (log2)
What did I do wrong?

Math  Logarithmic  Reiny, Thursday, December 13, 2007 at 6:57pm
you are wrong and the textbook answer, the way you stated is, is wrong.
2^(5x6) = 7
log[2^(5x6)] = log7
(5x6)log2 = log7
5x6 = log7/log2
5x = log7/log2 + 6
x = (log7/log2 + 6)/5

Math  Logarithmic  Anonymous, Saturday, October 29, 2016 at 11:16am
Without using a calculator, find the value of the following logarithmic expression.
log7 1
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