Posted by **Anonymous** on Thursday, December 13, 2007 at 6:39pm.

Solve:

2^(5x-6) = 7

My work:

log^(5x-6) = log7

5x - 6(log2) = log7

5x = log7 + 6(log2)

x = (log7 + log2^6) / 5

And textbook answer:

(log7) / (log2)

What did I do wrong?

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