Posted by anon on Thursday, December 13, 2007 at 12:28pm.
What you have finds the pH for a solution of NaH2AsO4.
For a solution of Na3AsO4,
write the hydrolysis equation.
AsO4^-3 + HOH ==> HAsO4^-2 + OH^-
Kb = Kw/K3 = (OH^-)^2/(AsO4^-3)
You know Kw, K3 (look up K3 for H3AsO4), and (AsO4^-3= 0.0400 M)
This gives (OH^-). Convert to pOH and then to pH. Post your work if you get stuck.
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