Help me solve this!!
Joeys father stops at the gas station to buy gas. The car has a 16 gallon tank, and the feul gauge says there are 3-4 of a tank of gas. If joeys dad buys 6 gallons of gas, what fraction of the tank will the car´s feul gauge read??
thanks,
tayler
The gas gauge is not accurate. If it was reading 3/4 full, there should have been 12 gallons in the car, and it could not have held 6 more. Many cars are like that. When they say 1/2 to 3/4 full, there is really less than that amount available, but then they say E, there is usually one or two gallons still available.
To solve this problem, we need to determine the fraction of the tank that the car's fuel gauge will read after Joey's dad buys 6 gallons of gas.
First, let's determine the amount of gas in the tank before Joey's dad buys any gas. The fuel gauge indicates that there are 3-4 of a tank of gas, which means that there are 3/4 * 16 = 12 gallons of gas in the tank.
Next, let's calculate the amount of gas in the tank after Joey's dad buys 6 gallons of gas. We add the 6 gallons to the initial amount of gas, which gives us a total of 12 + 6 = 18 gallons of gas in the tank.
Finally, we need to calculate the fraction of the tank that the car's fuel gauge will read. Since the car has a 16-gallon tank, and there are now 18 gallons of gas in the tank, the fraction of the tank that the fuel gauge will read is 18/16.
We can simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 2 in this case. Simplifying gives us a fraction of 9/8.
Therefore, the car's fuel gauge will read 9/8 of a tank of gas after Joey's dad buys 6 gallons.