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December 21, 2014

December 21, 2014

Posted by **mike** on Wednesday, December 12, 2007 at 9:53pm.

logbase2x+logbase2 3= 3

i factored the left side but i have no idea what to do with the right side.

- functions math -
**Anonymous**, Wednesday, December 12, 2007 at 9:57pmlog_2(3)x + log_2(3) = 3

log_2(3)x + log_2(3) = log_2(2^3)

log_2 [(x)(3)] = log_2(8)

(x)(3) = 8

x = 8/3

Log_2 = log base 2

2^3 = 2 to the power of 3

(x)(3) = x times 3

8/3 = 8 over 3

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