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December 18, 2014

December 18, 2014

Posted by **Rose** on Wednesday, December 12, 2007 at 9:24pm.

- college math -
**Damon**, Wednesday, December 12, 2007 at 9:55pmNow here the order of things in the group does not matter so we want the number of combinations of 7 out of 19

C(n,r)= n!/[r!(n-r)!]

= 19!/[7!(12!)]

=19*18*17*16*15*14*13/(7*6*5*4*3*2)

=19*3*17*4*1*13/1

=50,388

check my arithmetic for sure if you have a calculator that does factorials.

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