college math
posted by Rose on .
14. (2 pts) How many different ways are there for an admissions officer to select a group of 7 college candidates from a group of 19 applicants for an interview?

Now here the order of things in the group does not matter so we want the number of combinations of 7 out of 19
C(n,r)= n!/[r!(nr)!]
= 19!/[7!(12!)]
=19*18*17*16*15*14*13/(7*6*5*4*3*2)
=19*3*17*4*1*13/1
=50,388
check my arithmetic for sure if you have a calculator that does factorials.