Posted by Anne on Wednesday, December 12, 2007 at 8:26pm.
So tell us your problem. What is it you don't understand.
Is it okay to have a negative temperature (in degrees Celsius) in this case?
Combustion reactions give off energy, as this one does; therefore, the temperature will rise. The question asks for how much the T will rise. So, no, I wouldn't expect the T to go down.
But I got an answer of 42.5K, which means when I convert it to degrees Celsius I get 42.5K - 273 K = -23.05 degrees Celsius.
Does this sound weird to you then?
Yes, it's weird. But your answer is correct; you're just confused on what your answer is. I worked the problem and I have 42.5 degrees BUT THAT IS DELTA T. That IS the rise in degrees C or degrees K (both are equivalent). The problem didn't ask for the T, it asked for delta T and that is what the equation is.
delta H = delta E = Cp*delta T
885.4 kJ/mol* 4.2 mol = 87.5 kJ*delta T.
Solve for delta T = 42.5 degrees K (or 42.5 degrees C.).
Glad I could help.
Oh, I see now. I really appreciate your help :) Have a wonderful day!
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