[ (x-3)(x+1) / (3x+11) ] = 0
How would I solve this equation?
I don't know how to isolate for x.
Answer: 7
Multiply both sides by (3x+11)
(x-3)(x+1) = 0
x=3 or x = -1
I can't do that because the answer is 7
Try 7
[(7-3)(7+1)/(21+11) ] = 0
no way
your problem with 7 put in as x.
49-14-3 32
-------- = ---- = 0
21+11 32
To solve the equation [(x-3)(x+1) / (3x+11)] = 0, you need to first understand that a fraction is equal to zero when its numerator is equal to zero. So the numerator (x-3)(x+1) must be equal to zero for the entire expression to equal zero.
To isolate for x, you can set each factor in the numerator to zero separately and solve for x:
First, set x-3 = 0:
x - 3 = 0
x = 3
Next, set x+1 = 0:
x + 1 = 0
x = -1
Therefore, the solutions to the equation [(x-3)(x+1) / (3x+11)] = 0 are x = 3 and x = -1.
(Note: In the original question, the answer given as "7" is not correct. The solutions are x = 3 and x = -1)