Tuesday

January 17, 2017
Posted by **STUCK** on Tuesday, December 11, 2007 at 11:00pm.

x^2 - 10x - 24

A. (x + 4)(x - 6)

B. (x + 6)(x - 4)

C. (x + 2)(x - 12)

D. (x + 12)(x - 2)

2, x^2 - 36 = 0

A. (1 + square root of 3, 1 - square root of 3)

B. (-6,6)

C. No solution

D. None of these

3, Factor each expression

49 x^9 - 25 y^2

A. (7x^2 - 5y)(7x^2 + 5y)

B. (7x^3 - 5y)(7x + 5y)

C. (7x^2 - 5y)^2

D. None of these

4, Factor each expression

x^2 - 9

A. (x - 3)(x - 3)

B. (x - 9)(x + 1)

C. (x - 3)(x + 3)

D. None of these

5, Factor each expression

3 x^2 - 2x - 8

A. (3x + 2)(x + 4)

B. (2x + 4)(2x - 4)

C. (3x - 2)(x - 4)

D. None of these

6, 1 - 5 x^2 = -3x

A. (3/10 + square root 29/10, 3/10 - square root 29/10)

B. (-3/10 + square root 29/10, -3/10 - square root 29/10)

C. No solution

D. None of these

7, x^2 - 4x + 1 = 0

A. (2 + square root of 3, 2 - square root of 3)

B. (-2 + square root of 3, -2 - square root of 3)

C. No solution

D. None of these

8, Find each product

(x - 6y)^2

A. x^2 - 12xy + 36y^2

B. x^2 + 12xy + 36y^2

C. x^2 - 12xy - 36y^2

D. None of these

9, Find each product

(x - 4)(x + 4)

A. x^2 - 8x -16

B. x^2 - 16

C. x^2 + 2x + 16

D. None of these

10, Find each product

(3x - 2)(2x + 5)

A. 5x^2 - 11x - 10

B. 6x^2 - 11x -10

C. 6x^2 + 9x +10

D. None of these

11, The cube of a certain whole number is 48 more than the square of the same number. What is the number?

A. 3

B. 4

C. 5

D. 6

12, If a quadratic equation can be solved, how many solutions are there?

A. 1

B. 1 or 2

C. 2

D. 3

13, 3 x^2 - 2 = 4x

A. (-2,4)

B. (2/3 + square root of 10/3, 2/3 - square root of 10/3)

C. (-2/3 + square root of 10/3, -2/3 - square root of 10/3)

D. None of these

14, The product of two consecutive positive integers is 132. What are the numbers?

A. 10, 11

B. 11, 12

C. 12,13

D. 13,14

15, x^2 - 4x - 121 = -4x

A. (-10, 12)

B. (-9, 9)

C. (-11, 11)

D. None of these

- ALGEBRA -
**Reiny**, Tuesday, December 11, 2007 at 11:10pmWow, do you actually expect somebody to do all those questions for you??

Why not show some work, and I would be ever so happy to critique it.

for example in the first five, why don't you expand the answers that are given to see which matches your question?

same thing for problems such as #10, just expand it and see what happens.- ALGEBRA -
**STUCK**, Tuesday, December 11, 2007 at 11:25pmNO I DON'T EXPECT ANYONE TO DO THEM FOR ME I AM IN HOMESCHOOL AND I HAVE NOT BEEN IN AN ALGEBRA CLASS IN A WHILE SO WHEN THEY GAVE ME A LESSON ON IT I WAS BLANK I DON'T REMEMBER ANYTHING FROM REGULAR SCHOOL AND JUST NEED HELP FINDING OUT WHERE TO BEGIN OR I NEED AN EXAMPLE PROBLEM WHERE I CAN FOLLOW EACH STEP.TY

- ALGEBRA -
- ALGEBRA -
**~christina~**, Wednesday, December 12, 2007 at 1:18amYou could always google "factoring expressions" and seeing what sites come up and look at the examples given.

It should help if you don't know where to start.