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algebra

posted by on .

solve the following using substitution
8x-4y=16
y=2x-4

8x-4(2x-4)=16
8x-8x+16=16
0x+16=16
so what do i do now?

  • algebra - ,

    Those two equations are the same.
    Look at your first equation dividing both sides by 4
    2 x - y = 4 or y = 2x-4 which is the second equation exactly. There is no intersection of a line with itself in a point. The system of two equations given has no solution.

  • algebra - ,

    Thank you that is what I thought but wasn't sure when I did not come up with an answer.

  • algebra - ,

    uyg

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