posted by caren on .
how do i write a net ionic equation for Lead (II) Nitrate and Sodium Carbonate react to form Lead Carbonate and Sodium Nitrate??
Step 1. Write molecular equation:
Pb(NO3)2(aq) + Na2CO3(aq) ==> PbCO3(s) + 2NaNO3(aq)
Step 2. Separate into ions; e.g., Pb^+2(aq) + 2NO3^-(aq) + etc. Solids (those with (s) are not soluble; therefore, do not separate them. Any weak electrolytes also stay as the molecule; you don't have any of those in this equation.
Step 3. Cancel any ions common to both sides. What remains is the net ionic equation.
I will give you the completed equation BUT you should go through to make sure you can do these.
Pb^+2(aq) + CO3^-2(aq) ==> PbCO3(s)
Note that the Na^+ and the NO3^- ions cancel; they don't enter into the reaction.