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September 16, 2014

September 16, 2014

Posted by **kile** on Monday, December 10, 2007 at 11:06pm.

1.

Infinity (Summation sign) n = 1

1/6n^2

2.

Infinity (Summation sign) n = 1

(0.6)^n-1

- Calculus III -
**drwls**, Tuesday, December 11, 2007 at 2:08am1. Apparently you mean the sum from n=1 to n=infinity of 1/(6n^2)

= 1/(6*1) + 1/(6*4) + 1/6*9)

= (1/6)(1 + 1/4 + 1/9 + 1/16 + ...)]

This is not a geometric series. The ratio of successive terms is not a constant.

2. 0.6 + 0.6^2 + 0.6^3 + ...

= 0.6(1 + 0.6 + 0.6^2 + ...]

= 0.6/[1 - 0.6)= 1.5

This is a geometric series.

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