Posted by julia on Monday, December 10, 2007 at 9:48pm.
A 0.15 kg baseball moving at +26 m/s is slowed to a stop by a catcher who exerts a constant force of 390 N. How long does it take this force to stop the ball? How far does the ball travel before stopping?
plz plz plz help!!

physics!! plz answer me!  drwls, Tuesday, December 11, 2007 at 6:36am
Use the impulsemomentum wethod to answer this question. The impulse is the average force Fav, multipled bu the tme that it is applied (which is the time it takes to decelerate the ball).
Fav * T = 0.15 kg * 26 m/s
We only need the absolute value of the force, so never mind the minus sign in front of 390N.
T = .015*26/390 = ? seconds
The distance X travelled while stopping equals average velocity x Time
X = (1/2)V^2*M/Fav

physics!! plz answer me!  Bill, Tuesday, February 9, 2016 at 2:25pm
.01s
Answer This Question
Related Questions
 Physics!!!!!!  A 0.18 kg baseball moving at +26 m/s is slowed to a stop by a ...
 physics  A 0.20 kg baseball moving at +25.20 m/s is slowed to a stop by a ...
 Physics  A 0.17 kg baseball moving at +20.80 m/s is slowed to a stop by a ...
 Physics Impulse part 2  1) A 0.50 kg object is at rest. A 3.00 N force to the...
 physics  how much force is required to stop a 100 mi/hr fastball? Assume the ...
 physics  how much force is required to stop a 100 mi/hr fastball? assume the ...
 PHYSICS  A catcher “gives” with a baseball when catching it. If the baseball ...
 physics  A 3.8 kg ball is rolling along a slippery road at 1.5 m/s E. It then ...
 physics  When catching a baseball, a catcher's glove moves by 11 cm along the ...
 physics  When catching a baseball, a catcher's glove moves by 12 cm along the ...
More Related Questions