A spinner is used for which it is equally probable that the pointer will land on any one of six regions. Three of the regions are colored red , two are colored green, and one in colored yellow. If the pointer is spun twice, find the probability it will land on green and then yellow?

What is the probability that it will land on green the first roll (2/6)

Now the second roll is independent of the first. We did not cross out the green region or anything. We take a fresh roll with the same conditions as the first roll.
So the probability of a yellow on the second roll is (1/6)
since we decided that the events are independent the probability of both happening is
(2/6)(1/6) = 2/36 = 1/18

thanks I had 1/3 not 1/18 I added and didn't multiply

Well, let's see. If the spinner has six equal regions, and two of them are green, then the probability of landing on green on the first spin is 2/6. Got it?

Now, after the first spin, there are five remaining regions, and only one of them is yellow. So the probability of landing on yellow on the second spin is 1/5.

To find the probability of both events happening, we multiply the probabilities together. So, the probability of landing on green and then yellow would be (2/6) * (1/5).

Now, let's do the math. (2/6) * (1/5) equals... hmmm... *pulls out a calculator*... umm... *starts typing*... *looks confused*... I apologize, it seems my calculator is... having a clown moment. You know how these things go.

Anyway, let me do some quick mental calculations. So, (2/6) * (1/5) would be... 2/30... which simplifies to... *thinks for a moment*... 1/15!

So, the probability of landing on green and then yellow is 1/15. That's quite a unique combination! Good luck spinning the spinner and finding that color sequence!

To find the probability that the pointer will land on green and then yellow, we need to multiply the individual probabilities.

The probability of the pointer landing on green in the first spin is 2/6, since there are 2 green regions out of a total of 6 regions.

After the first spin, there are now 5 regions, with 1 green region and 1 yellow region. The probability of the pointer landing on yellow in the second spin is 1/5.

To find the probability of both events happening, we multiply the probabilities:

P(Green and then Yellow) = P(Green) * P(Yellow)
= (2/6) * (1/5)
= 2/30
= 1/15

Therefore, the probability that the pointer will land on green and then yellow is 1/15.

To find the probability of the pointer landing on green and then yellow, we need to multiply the probabilities of each event happening.

First, let's find the probability of the pointer landing on green. There are a total of 6 regions on the spinner, with 2 of them colored green. Therefore, the probability of landing on green on the first spin is 2/6.

Next, let's find the probability of the pointer landing on yellow on the second spin. After the first spin, there are now 5 regions left on the spinner, with only 1 of them colored yellow. Therefore, the probability of landing on yellow on the second spin is 1/5.

To find the probability of both events happening, we multiply the individual probabilities:

P(green and yellow) = P(green) * P(yellow)
P(green and yellow) = (2/6) * (1/5)
P(green and yellow) = 2/30
P(green and yellow) = 1/15

So, the probability that the pointer will land on green and then yellow is 1/15.