Aluminum sulfate reacts with sulfuric acid to produce aluminum sulfate and hydrogen gas. How many grams of aluminum sulfate would be formed if 250g H2 SO4 completely react with aluminum?

I think you mean Al reacts with sulfuric acid.....

Write the equation and balance it.
Convert 250 g H2SO4 to mols. mols = grams/molar mass.
Using the coefficients in the balanced equuation, convert mols H2SO4 to mols Al2(SO4)3.
Finally, ocnvert mols Al2(SO4)3 to grams. grams = mols x molar mass.
Post your work if you need further assistance.

To determine the grams of aluminum sulfate formed, we need to use the balanced chemical equation and the molar masses of aluminum sulfate and sulfuric acid.

Firstly, let's write the balanced chemical equation for the reaction:
3H2SO4 + 2Al → Al2(SO4)3 + 3H2

According to the equation, 3 moles of sulfuric acid react with 2 moles of aluminum to produce 1 mole of aluminum sulfate.

Step 1: Calculate the moles of sulfuric acid (H2SO4):
To find the moles of sulfuric acid, divide the given mass (250g) by its molar mass.

The molar mass of sulfuric acid (H2SO4) is:
2(1.01g/mol) + 32.07g/mol + 4(16.00g/mol) = 98.09g/mol

Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4
= 250g / 98.09g/mol

Step 2: Calculate the moles of aluminum sulfate (Al2(SO4)3):
From the balanced equation, we know that 2 moles of aluminum sulfate are produced for every 3 moles of sulfuric acid.

Moles of Al2(SO4)3 = Moles of H2SO4 × (2 mol Al2(SO4)3 / 3 mol H2SO4)

Step 3: Calculate the mass of aluminum sulfate (Al2(SO4)3):
To find the mass of aluminum sulfate, multiply the moles of aluminum sulfate by its molar mass.

The molar mass of aluminum sulfate (Al2(SO4)3) is:
2(26.98g/mol) + 3(32.07g/mol) + 12(16.00g/mol) = 342.15g/mol

Mass of Al2(SO4)3 = Moles of Al2(SO4)3 × Molar mass of Al2(SO4)3

Now, substitute the calculated values into the equation above to obtain the answer.