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August 30, 2014

August 30, 2014

Posted by **ajo** on Sunday, December 9, 2007 at 4:23pm.

Can anyone please give me some hints to do this?THANKS A LOT!

- physics -
**drwls**, Sunday, December 9, 2007 at 5:39pmFirst, compute the work done in method 1. That would be M g H = 45*9.8*3.0 sin A = 1323 sin A Joules. A is the angle of the place to the horizontal.

With the ramp, you do twice as much work, or 2646 J sin A. If 485 J of this was overcoming friction, the potential energy change was

2646 sin A - 485

This equals the potential energy change with method 1, or 1323 sin A. Therefore

2646 sin A -485 = 1323 sin A

485 = 1323 sin A

sin A = 0.367

A = ?

- physics -
**ajo**, Sunday, December 9, 2007 at 6:02pmi don't understand...this part:

the potential energy change was

2646 sin A - 485

This equals the potential energy change with method 1, or 1323 sin A. Therefore

2646 sin A -485 = 1323 sin A

485 = 1323 sin A

can you please explain it in details£¿

- physics -

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