Posted by Anthony on Saturday, December 8, 2007 at 11:49pm.
I explained this yesterday. You use the method of partial fractions, to rewrite
1/(q^2-v^2) as the sum of terms with
(q+v)and (q-v) in the denominator. When you integrate those two separate terms, you get the difference of two log terms.
Look up the method in your text or verify the integal in a table of integrals.
[1/(2q)] is a factor appears when the method of partial fractions is correctly applied.
"ln" is term that designates the natural (base e) logarithm of whatever follows. ln x is the integral of dx/x
ln (q+v) is the integral of dv/(q+v), with q being a constant. When you do the integration, you get the ln(q+v) - ln (q-v). Using the rules of logarithms, this can be written ln[(q+v)/(q-v)]. The 1/2q factor comes from the step of converting 1/(q^2-v^2) to two partial fractions.
Related Questions
Math - step 1: x = integral(from 0 to v) dv/(z^2-v^2) step 2: x = 1/2z ln((q+v...
chemistry - This question I really don't get it. I tried tried tried to ...
Greens Theorem - Can someone show me step by step how to work this problem out ...
calculus - can someone show me step by step how to evaluate the integral of 2(...
Calculus - 1/a+1 + 1/a-1 I solved this out by multiplying the (a+1) by (a-1) and...
Algebra - Can you please show me step by step to the answer you have given me. -...
Math - How to solve for x? (x/(x+1))+ ((2x-2)/x) = -1/(x+1) can someone show it ...
Pre-Algebra [urgent!] - I can't find the solution to this problem; can ...
math - At the county fair, the apple pies are lined up side-by-side for juding ...
pre algebra - please show me step by step how to solve the following equation -...
For Further Reading
