1.The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

A)
4 cm

B)
5 cm

C)
11 cm

D)
12 cm
answers
4x-8= 4(5)-8= 20-8= 12
2.3x - 2y = 6
answer
X=4 and Y=3

3*4=12
x = 2/3y + 2
3.solve. -3(x+1)=2(x-8)+3
ANSWER
X=2

I call the base b

then each leg is (4b-8)
then the perimeter is 2(4b-8)+b
so
2(4b-8)+b = 29

in the end you should get base b = 5 and the two equal legs are each 12

let the base be x

then each of the other sides is 4x-8

4x+8 + 4x+8 + x = 29
.
.
x=5
2x-8=12
then the triangle has base 5 and the other two sides are 12 each, it checks out

To find the length of one of the equal legs of the isosceles triangle, we first need to set up an equation based on the information given.

Let the length of the base be represented by 'x'. According to the problem, one of the equal legs is 8 cm less than 4 times the length of the base. So, the length of one of the equal legs can be represented as 4x - 8.

The perimeter of a triangle is the sum of the lengths of all three sides. In this case, the perimeter is given as 29 cm. Since an isosceles triangle has two equal legs, we can write the equation as:

x + (4x - 8) + (4x - 8) = 29.

Simplifying this equation, we get:

9x - 16 = 29.

Adding 16 to both sides of the equation, we get:

9x = 45.

Dividing both sides by 9, we get:

x = 5.

To find the length of one of the equal legs, we substitute the value of x back into the expression 4x - 8:

4(5) - 8 = 20 - 8 = 12.

Therefore, the length of one of the equal legs is 12 cm.

Therefore, the answer is D) 12 cm.