Posted by **mary** on Friday, December 7, 2007 at 1:47pm.

1.The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

A)

4 cm

B)

5 cm

C)

11 cm

D)

12 cm

answers

4x-8= 4(5)-8= 20-8= 12

2.3x - 2y = 6

answer

X=4 and Y=3

3*4=12

x = 2/3y + 2

3.solve. -3(x+1)=2(x-8)+3

ANSWER

X=2

- MATH -
**Damon**, Friday, December 7, 2007 at 2:47pm
I call the base b

then each leg is (4b-8)

then the perimeter is 2(4b-8)+b

so

2(4b-8)+b = 29

in the end you should get base b = 5 and the two equal legs are each 12

- MATH -
**Reiny**, Friday, December 7, 2007 at 2:55pm
let the base be x

then each of the other sides is 4x-8

4x+8 + 4x+8 + x = 29

.

.

x=5

2x-8=12

then the triangle has base 5 and the other two sides are 12 each, it checks out

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