Posted by rodrigo on Friday, December 7, 2007 at 12:47pm.
h(-x) = f(-x)g(-x)
f(-x) = -f(x)
g(-x) = -g(x) ---->
f(-x)g(-x) = f(x)g(x) = h(x)
So:
h(-x) = h(x)
g(x)*f(x) is an even function, since both f and g change signs when x is replaced by -x
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