Posted by **Tim** on Friday, December 7, 2007 at 12:22am.

At 3 p.m., Brunhilde headed north at 30 kilometers per hour. Two hours later Ludwig headed south at 40 kilometers per hour. At what time will they be 340 kilometers apart?

I know that the distance from Brunhilde(Db) plus the distance from Ludwig(Dl) is equal to 340, which is translated as (Tb)(Rb)+(Tl)(Rl)=340, "T" standing for time, and "R" standing for rate...so I substitue in the rates to get 40Tb + 30Tl=340, but the answer is wrong..the book has it as 9 p.m....what am I doing wrong!!!!?

- Algebra..please check my work!! -
**drwls**, Friday, December 7, 2007 at 12:29am
They separate at a rate of 30 + 40 =

70 km/hr, since they are going in opposite directions. It takes 340/70 = 4.857 hours to become 340 km apart. That would be at 8:51 PM, since 0.857 x 60 = 51+ minutes. Are you sure they didn't ask for the time when they are 350 km apart, not 340? Then the answer would be exactly 9 PM

- Algebra..please check my work!! -
**Tim**, Friday, December 7, 2007 at 12:54am
Yea the answer in the back of the book has it at 9 p.m. ,and yea they do ask for the time when their 340 kilometers apart, interesting, could the book be wrong?lol

- Algebra..please check my work!! -
**Tim**, Friday, December 7, 2007 at 1:07am
When you divided 340/70 and came up with 4.857, how'd you come up with 8?

- Algebra..please check my work!! -
**Reiny**, Friday, December 7, 2007 at 1:36am
The book is correct.

Let the time passed after Ludwig left be t hours, remember he left 2hours after her, so she already went 60 km

So the distance that Brunhilde went is 60+30t

and the distance that Ludwig went is 40t

so....

60 + 30t + 40t = 340

70t = 280

t = 4

So they are 340 km apart 4 hours after Ludwig left, but he left at 5 pm, so they are apart 340 km at 9 pm

- Algebra..please check my work!! -
**drwls**, Friday, December 7, 2007 at 3:05pm
Sorry; I misread the problem and neglected the time delay

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