Posted by mel on Thursday, December 6, 2007 at 11:30pm.
E = 2.180 x 10^-18 J/n2 where n is the principle quantum number of 2 or 4 for your two problems.
Then E = hc/lambda. h is Planck's constant, c is speed of light, lambda is wavelength IN METERS. Solve for lambda.
Related Questions
Chemistry!! - Calculate the maximum wavelength of light capable of removing an ...
Chemistry - Calculate the wavelength of light emitted when each of the following...
Chemistry!! - bobpursley please - Calculate the maximum wavelength of light ...
Atomic physics - 1)What is the longest wavelength light capable of ionizing a ...
Physics - A hydrogen atom is in its third excited state (n=4). Using Bohr theory...
Physics-Astronomy - Hello, I have no idea how to do the following question. Any ...
Atomic physics - 5)a. Electrons accelerated by a potential difference of 12.23 V...
chem - How much energy is required to ionize a hydrogen atom in its ground (or ...
Chemistry - A hydrogen atom electron in an excited state with n = 7 drops to a ...
chem 115 - The first ionization energy is the energy necessary to completely ...
For Further Reading