Posted by mel on Thursday, December 6, 2007 at 11:30pm.
calculate the max wavelength of light capable of removing an electron for a hydrogen atom from the energy state characterized by the following :
n=2 in nm
n=4 in nm

chem  DrBob222, Thursday, December 6, 2007 at 11:45pm
E = 2.180 x 10^18 J/n^{2} where n is the principle quantum number of 2 or 4 for your two problems.
Then E = hc/lambda. h is Planck's constant, c is speed of light, lambda is wavelength IN METERS. Solve for lambda.
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