If x1 and y1 is (2,2) and x2 and y2 is(3,2) what is the y intercept form? I'm confused on how to work the problem out step by step

y=mx+b

When x goes up from 2 to 3

Y stays the same at 3. (the slope is in fact zero unless you have a typo)
In general
(y-Y1)/(x-X1) = slope = (Y2-Y1)/(X2-X1)
here assuming no typo
(y - 2)/(x-2) = (2-2)/(3-1) = 0
so
y-2 = 0 (x-2)
y - 2 = 0 x + 0
y = 0 x + 2
y = 0 x + 2
or simply y = 2 of course, since it is 2 with no slope up or down.

To find the y-intercept form of a linear equation, we need two pieces of information: the slope and the y-intercept.

Step 1: Find the slope (m):
The slope (m) of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the formula:

m = (y2 - y1) / (x2 - x1)

In this case:
(x1, y1) = (2, 2)
(x2, y2) = (3, 2)

m = (2 - 2) / (3 - 2) = 0 / 1 = 0

So, the slope (m) is 0.

Step 2: Find the y-intercept (b):
The y-intercept (b) is the value of y when x = 0. To find it, we can use one of the given points (x1, y1) and substitute the x and y values into the equation:

y1 = m * x1 + b

Using the point (2, 2):

2 = 0 * 2 + b
2 = b

So, the y-intercept (b) is 2.

Step 3: Write the equation in y-intercept form:
Now that we have the slope (m = 0) and the y-intercept (b = 2), we can write the equation in y-intercept form, which is y = mx + b.

Plugging in the values:

y = 0x + 2

Simplifying:

y = 2

Therefore, the y-intercept form of the equation is y = 2.