ok i asked 4 help earlear ang got it but now im stuck again
(2,5) M=1/2
the book says to
"write an equation of the line that passws through the point and has the given slope. write the equation in slope-intercept form."
but how do i do this with a fraction the book dose not explane.
please help!!!!!
The fraction means that the slope goes up in y one unit for every two units in x
(y-5)/(x-2) = 1/2
You can write this lots of ways.
For example multiply both sides by (x-2)
y-5 = (1/2) (x-2)
y - 5 = (1/2) x - 1
y = (1/2) x + 4
the slope m = (1/2)
and along the y axis, where x = 0 the y axis intercept (b) is 4
CHECK
when x = 2
y = (1/2)(2) + 4
y = 1 + 4
y = 5
so indeed the line goes through (2,4)
ah (2,5) I mean
Hay thx that was confusing me thanks a lot
To write the equation of a line that passes through a given point and has a specific slope, you can use the slope-intercept form of a linear equation, which is:
y = mx + b
where "m" represents the slope and "b" represents the y-intercept.
In this case, you are given the point (2,5) and the slope m = 1/2. To find the equation, you can substitute the values into the slope-intercept form.
Replace "m" with the given slope:
y = (1/2)x + b
Now, you need to find the value of "b," which is the y-intercept. To do this, substitute the coordinates of the given point (2,5) into the equation:
5 = (1/2)(2) + b
Simplify and solve for "b":
5 = 1 + b
b = 5 - 1
b = 4
Now that you have the value of "b", you can write the equation in slope-intercept form:
y = (1/2)x + 4
So, the equation of the line that passes through the point (2,5) with a slope of 1/2 is y = (1/2)x + 4.