Monday

September 22, 2014

September 22, 2014

Posted by **Anthony** on Thursday, December 6, 2007 at 1:05am.

x = integral(from 0 to v) dv/(z^2-v^2)

step 2:

x = 1/2z ln((q+v)/(q-v))

How do you get from step 1 to step 2 ?

- Math -
**drwls**, Thursday, December 6, 2007 at 2:40amThe indefinite integral of

dv/(z^2-v^2),

with z being a constant, is

[1/(2z)]log[(z+v)/(z-v)]

Evaluate that at v=v' and subtract the value for v=0, to get the definite integral.

The method of partial fractions can used to get the integral. It involves rewriting 1/[(z^2-v^2} as

[1/(2z)][1/(z+v) - 1/(z-v)]

**Answer this Question**

**Related Questions**

ALGEBRA HELP - When solving the equation, what property was used to go from step...

Quick math help - In which step below does a mistake first appear in simplifying...

Algebra help - f(x)=x^3-4x^2-x+4 How do I find the x-intercept for this? This is...

pre algebra - solve the equation step by step.list each step along with the ...

Algebra 1--Step-by-Step - Can someone show me how to solve these step-by-step? ...

algerbra - solve the equation step by step list each step along with the ...

english! - Make sure you understand the topic(s) is a step in the research ...

geometry - The figure shows some of the steps Jane took to draw a line segment ...

Algebra1 - I am solving for linear equations and I'm wondering if I did Step 3 ...

chemistry step by step for me thank a lot - What is the weight of ca(oh)2 ...