Posted by **Anthony** on Thursday, December 6, 2007 at 1:05am.

step 1:

x = integral(from 0 to v) dv/(z^2-v^2)

step 2:

x = 1/2z ln((q+v)/(q-v))

How do you get from step 1 to step 2 ?

- Math -
**drwls**, Thursday, December 6, 2007 at 2:40am
The indefinite integral of

dv/(z^2-v^2),

with z being a constant, is

[1/(2z)]log[(z+v)/(z-v)]

Evaluate that at v=v' and subtract the value for v=0, to get the definite integral.

The method of partial fractions can used to get the integral. It involves rewriting 1/[(z^2-v^2} as

[1/(2z)][1/(z+v) - 1/(z-v)]

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