Posted by **sam** on Wednesday, December 5, 2007 at 11:59pm.

The Parkhursts used 160 yd of fencing to enclose a rectangular corral to divide it into two parts by a fence parallel to one of the shorter sides. Find the dimensions of the corral if its area is 1000 yd ^2 ( yd has a small 2 above the d)

SO CONFUSED NEED TO SHOW STEPS

- MATH problem help had typo -
**drwls**, Thursday, December 6, 2007 at 12:09am
I answered this already

- MATH problem help had typo -
**Reiny**, Thursday, December 6, 2007 at 12:24am
The the width be x yds

let the length be y yds

then 3x + 2y = 160

y = (160-3x)/2

area = xy

x(160-3x)/2 = 1000

160x - 3x^2 = 2000

3x^2 - 160x + 2000 = 0

(x-20)(3x - 100)= 0

x = 20 or x= 100/3

if x=20, then y = 50

if x=100/3 then y = 30

Case 1, x=20, y =50

3(20) + 2(50) = 160, area = 20*50 = 1000

Case 2 x = 100/3, y =30

3(100/3) + 2(30) = 160, area = 30*100/3 = 1000

So the dimensions could be 20 by 50, with the third side parallel to the 20

or

the dimensions could be 100/3 by 30 with the third side parallel to the 100/3 side.

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