Monday
March 27, 2017

Post a New Question

Posted by on .

The Parkhursts used 160 yd of fencing to enclose a rectangular corral to divide it into two parts by a fence parallel to one of the shorter sides. Find the dimensions of the corral if its area is 1000 yd ^2 ( yd has a small 2 above the d)

SO CONFUSED NEED TO SHOW STEPS

  • MATH problem help had typo - ,

    I answered this already

  • MATH problem help had typo - ,

    The the width be x yds
    let the length be y yds

    then 3x + 2y = 160
    y = (160-3x)/2

    area = xy
    x(160-3x)/2 = 1000
    160x - 3x^2 = 2000
    3x^2 - 160x + 2000 = 0
    (x-20)(3x - 100)= 0
    x = 20 or x= 100/3

    if x=20, then y = 50

    if x=100/3 then y = 30

    Case 1, x=20, y =50
    3(20) + 2(50) = 160, area = 20*50 = 1000

    Case 2 x = 100/3, y =30
    3(100/3) + 2(30) = 160, area = 30*100/3 = 1000

    So the dimensions could be 20 by 50, with the third side parallel to the 20

    or
    the dimensions could be 100/3 by 30 with the third side parallel to the 100/3 side.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question