Posted by Lindsay on Wednesday, December 5, 2007 at 5:23pm.
Initial puck kinetic energy
= work done against friction
(1/2) M V^2 = M*g*muk*X
muk is the coefficient of kinetic friction that you want. M cancels out, so you don't need to know it.
X is the distance that the puck slides while coming to a stop.
muk = (1/2) V^2/(g X)
That's all there is to it!
Ahh ok, I didn't realize the masses cancel out. But of course you're right.
That really was easy. :)
given:mass m= 20 kilogram ,force = 50 N from newton 2nd law,
f=ma where a=acceleration of the box
a=f over m= 50 over 20=2.5
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