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September 3, 2014

September 3, 2014

Posted by **Lindsay** on Wednesday, December 5, 2007 at 4:16pm.

(a) Find the size of the horizontal force which the car applies on the road while stopping.

(b) Find the stopping distance of that same car when it is traveling up a 18.1 deg slope, and it locks its wheels while traveling at 34.7 m/s (77.7 mi/hr). Assume that muk does not depend on the speed.

This is making no sense to me. Can I please have some help?

- Physics -
**drwls**, Wednesday, December 5, 2007 at 4:30pm(a) (Force) x (stopping distance) = kinetic energy converted to heat

= (1/2) M V^2

Solve for F

(b) In this case, the initial kinetic energy is converted to both gravitational potential energy and heat.

The horizontal force will be whatever you get in Part (a), multiplied by cos 18.1 (0.9505). That is becasue the kinetic friction force is proportion to the normal component of the weight. Call this force F'

(Frictional work done) + (Potential energy increase) = (Initial kinetic energy)

F'*X + M g (X sin 18.1) = (1/2) M V^2

Solve for the new value of X.

The second term on the left is the increase in gravitational potential energy as the car sises up the slop.

- Physics -
**Lindsay**, Wednesday, December 5, 2007 at 4:49pmI came up with 5079 N as my answer to a. Is that correct?

- Physics -
**Lindsay**, Wednesday, December 5, 2007 at 5:16pmYeppp n/m it is correct. Thanks a lot. :)

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