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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Wednesday, December 5, 2007 at 11:52am.

(a) g(x)= 2sinx + 2cos^(2)x; [0,2pie]

(b) f(x)=x^(4)-2x^(3)+3; [-1,2]

- CALCULUS -
**drwls**, Wednesday, December 5, 2007 at 6:04pmSet the derivatives equal to zero to determine the location of the extreme values.

Determine what the second derivative is at those points to tell maxima from minima. (Positive second derivative means a minimum). If the second derivative is zero, the situation is more complex. You might try plotting it out.

For example, in (b),

f'(x) = 4x^3 -6x^2 = 0

x^2(4x - 6) = 0

x = 0 or 3/2

f"(x) = 12x^2 -12x

When x = 3/2, f"(x) = 9

So x = 1.5 is a minimum location

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