Posted by **Lindsay** on Wednesday, December 5, 2007 at 10:47am.

A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the train is moving at 59.7 km/hr, in how short a distance can the train be stopped with a constant acceleration without causing the crates to slide?

I've tried this and I still can't get it. Can someone please show me the steps?

- Physics -
**drwls**, Wednesday, December 5, 2007 at 11:35am
Max friction force = M g u

The equals M a when it is on the verge of slipping.

Therefore a = u g is the maximum deceleration rate. u is the static coefficient of friction, 0.27

a = 2.646 m/s^2

To get the stopping distance X, use

V = sqrt (2 a X)= sqrt (2 u g X)

Convert the V = 59.7 km/hr to m/s units before using that equation.

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