Post a New Question


posted by .

A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the train is moving at 59.7 km/hr, in how short a distance can the train be stopped with a constant acceleration without causing the crates to slide?

I've tried this and I still can't get it. Can someone please show me the steps?

  • Physics -

    Max friction force = M g u
    The equals M a when it is on the verge of slipping.
    Therefore a = u g is the maximum deceleration rate. u is the static coefficient of friction, 0.27
    a = 2.646 m/s^2
    To get the stopping distance X, use
    V = sqrt (2 a X)= sqrt (2 u g X)
    Convert the V = 59.7 km/hr to m/s units before using that equation.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question