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April 20, 2014

April 20, 2014

Posted by **Jessica** on Wednesday, December 5, 2007 at 3:44am.

- Math -
**xX_Supaman_Xx**, Wednesday, December 5, 2007 at 5:25amd/dx x^2+3x = 2x+3

- Math -
**Reiny**, Wednesday, December 5, 2007 at 8:12amthe derivative of a function f(x) is

Limit [f(x+h) - f(x)]/h

h--> 0

so derivative of x^2 + 3x =

Lim[(x+h)^2 + 3(x+h) - x^2 - 3x]/h =

h--> 0

Lim [2hx + h^2 + 3h]/h =

h--> 0

Lim [2x + h + 3\]

h--> 0

= 2x + 3

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