Posted by **Tia** on Tuesday, December 4, 2007 at 11:54am.

In a physics lab experiment, a student immersed 205 one-cent coins (each having a mass of 3.00 g *.003kg) in boiling water. After they reached thermal equilibrium, she quickly fished them out and dropped them into 0.244 kg of water at 20.0 C in an insulated container of negligible mass.

What was the final temperature of the coins? [One-cent coins are made of a metal alloy - mostly zinc - with a specific heat capacity of 390 J/(kg*K).]

I know that:

Mass,coins=.615 kg

Mass,water=.244 kg

c=390 J/(kg*K)

Ti,water=20 C

I'm just not quite sure what equation to put them in...

- Physics help please -
**DrBob222**, Tuesday, December 4, 2007 at 12:30pm
Heat lost by the coins + heat gained by the water = 0

mass x specific heat x (Tf - Ti) + mass x specific heat x (Tf - Ti) = 0

Tf is final T. Ti is initial T.

Post your work if you get stuck.

- Physics help please -
**Avinaash**, Thursday, December 2, 2010 at 7:04pm
how to write up a lab on specific heat capacity

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