Posted by Tia on Tuesday, December 4, 2007 at 11:54am.
In a physics lab experiment, a student immersed 205 onecent coins (each having a mass of 3.00 g *.003kg) in boiling water. After they reached thermal equilibrium, she quickly fished them out and dropped them into 0.244 kg of water at 20.0 C in an insulated container of negligible mass.
What was the final temperature of the coins? [Onecent coins are made of a metal alloy  mostly zinc  with a specific heat capacity of 390 J/(kg*K).]
I know that:
Mass,coins=.615 kg
Mass,water=.244 kg
c=390 J/(kg*K)
Ti,water=20 C
I'm just not quite sure what equation to put them in...

Physics help please  DrBob222, Tuesday, December 4, 2007 at 12:30pm
Heat lost by the coins + heat gained by the water = 0
mass x specific heat x (Tf  Ti) + mass x specific heat x (Tf  Ti) = 0
Tf is final T. Ti is initial T.
Post your work if you get stuck.

Physics help please  Avinaash, Thursday, December 2, 2010 at 7:04pm
how to write up a lab on specific heat capacity
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