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January 28, 2015

January 28, 2015

Posted by **Anonymous** on Tuesday, December 4, 2007 at 12:24am.

I got the wrong answer.

(1m)(750N)+(2m)(500N)+(3m)(1000N)+(1.5m)(345N)=5267.5/3m=1756 N

(750N+500N+1000N+345N)-1756N=839N

The answer is suppose to be 1590N and 1005N.

- physics -
**drwls**, Tuesday, December 4, 2007 at 11:00amIn your first equation, the distance to the 1000N person (Joe) from the left cable is 2.5 m, not 3 m. The term on the right side of the equation should be F2 * 3 m, where F2 is the tension in the right cable. You divide the sum of momentws on the left by 3m to get the value of F2. Your equation is also wrong becasue you have moments on the left side and a force on the right side. They have to have the same units

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