The density of gold is 19.3 x 10^3 kg/m^3. What buoyant force does a .6 kg gold crown experience when it is immersed in water?

B=m_water*g
=p_water*v_water*g
=p_water*v_gold*g

and to find v_gold =m/density
and from there would p_water =1000kg/m^3?

To find the buoyant force experienced by the gold crown when it is immersed in water, we need to use the equation F_buoyant = density_water * volume_submerged * g.

First, let's calculate the volume of the gold crown.
The volume of an object is given by the equation V = m / density, where m is the mass of the object and density is the density of the material.

In this case, the mass of the gold crown is 0.6 kg, and the density of gold is 19.3 x 10^3 kg/m^3. So we can calculate the volume of the gold crown as follows:

V_gold = m_gold / density_gold
= 0.6 kg / 19.3 x 10^3 kg/m^3
≈ 3.11 x 10^(-5) m^3

Next, let's calculate the buoyant force using the formula:
F_buoyant = density_water * volume_submerged * g

The density of water is approximately 1000 kg/m^3, and the acceleration due to gravity is approximately 9.8 m/s^2.

F_buoyant = density_water * volume_submerged * g
= 1000 kg/m^3 * V_gold * 9.8 m/s^2
≈ 1000 kg/m^3 * 3.11 x 10^(-5) m^3 * 9.8 m/s^2
≈ 3.05 N

Therefore, the gold crown experiences a buoyant force of approximately 3.05 Newtons when immersed in water.