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December 18, 2014

December 18, 2014

Posted by **Lily** on Monday, December 3, 2007 at 7:16pm.

a)Product 563033256; Sum 51895

b)Product -43481220; Sum 28429

c)Product 2545124358; Sum -105619

I tried xy = product and x+y = sum, but it didn't work out... Can someone please help me?

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**Count Iblis**, Monday, December 3, 2007 at 7:42pmx+y = sum --->

y = sum - x

product = xy = x(sum-x) ------>

x^2 - sum x + product = 0

x = sum/2 ± sqrt[(sum/2)^2 - product]

There are two solutions because interchanging x and y in the solution will yield another solution. This means that you can take:

x = sum/2 - sqrt[(sum/2)^2 - product]

y = sum/2 + sqrt[(sum/2)^2 - product]

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**Lily**, Monday, December 3, 2007 at 8:23pmsorry, but I don't get it; how can I have two different solutiuons hen I'm only supposed to have one? Still, thanks.

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**Count Iblis**, Monday, December 3, 2007 at 9:03pmIf you have a solution and you interchange x and y then the sum and the poduct are the same, so that's another solution. This means that when we solve for x we get two solutions, the other solution bwing the value for y.

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**Lily**, Monday, December 3, 2007 at 9:27pmoh, okay, I get it now; thanks!

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