Posted by Scott on Sunday, December 2, 2007 at 11:50pm.
Do you mean sqrt(x+1) or sqrt x + 1?
If the former, the indefinite integral is [(x+1)^3/2]/(3/2)
Evaluate it at x = 9 and x = 0 and take the difference.
Area = (2/3)*[(10)^(3/2) - 1]
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