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July 25, 2014

July 25, 2014

Posted by **Scott** on Sunday, December 2, 2007 at 11:50pm.

y=square root of x + 1

from x=0 to x=9

Please walk me through each step.

- math calculus -
**drwls**, Monday, December 3, 2007 at 12:02amDo you mean sqrt(x+1) or sqrt x + 1?

If the former, the indefinite integral is [(x+1)^3/2]/(3/2)

Evaluate it at x = 9 and x = 0 and take the difference.

Area = (2/3)*[(10)^(3/2) - 1]

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