Posted by **john** on Sunday, December 2, 2007 at 6:53pm.

A baseball pitcher throws a baseball with an initial velocity of 133 feet per second at an angle of 20° to the hoizontal. The ball leaves the pitcher's hand at a height of 5 feet. Find parametric equations that descrive the motion of the ball as a function of time. How long is the ball in the air? When is the ball at its maximum height? What is the maximum height of the ball?

- calculus -
**drwls**, Sunday, December 2, 2007 at 7:40pm
The equations are:

x = 133 cos(35)* t

y = 5 + 133 sin 35 * t - (1/2) g t^2

It will remain in the air until y = 0. (Solve then y equation for t).

g = 9.8 m/s^2.

Maximum height is attained when

Vy = 133 sin 35 - gt = 0.

Solve for t. That is the time when the height is a maximum. Then insert that t into the equation for y(t). That will give you th3e maximum height.

- calculus -
**Carlos Garcia**, Wednesday, April 20, 2016 at 11:20am
how do you find the time in the air?? or maximum height??

## Answer This Question

## Related Questions

- calc - A pitcher throws a baseball straight into the air with a velocity of 72 ...
- Physics - A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If ...
- Physics - A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If ...
- Pre-Cal - A baseball player throws baseball at a velocity 139ft per second at an...
- physics - A baseball pitcher can throw a baseball at a speed of 42 m/s. If the ...
- Georgia Highlands college - Estimate the average force that a baseball pitcher's...
- Precalculus - For this problem, we will use the formula for position of an ...
- math - Baseball Nick throws a baseball upward with an initial velocity of 60 ...
- physic - a baseball pitcher throws a baseball with a speed of 4m/s.Estimate the ...
- college - A baseball pitcher throws a baseball with a speed of 38 . In throwing ...

More Related Questions