Wednesday

July 23, 2014

July 23, 2014

Posted by **john** on Sunday, December 2, 2007 at 6:53pm.

- calculus -
**drwls**, Sunday, December 2, 2007 at 7:40pmThe equations are:

x = 133 cos(35)* t

y = 5 + 133 sin 35 * t - (1/2) g t^2

It will remain in the air until y = 0. (Solve then y equation for t).

g = 9.8 m/s^2.

Maximum height is attained when

Vy = 133 sin 35 - gt = 0.

Solve for t. That is the time when the height is a maximum. Then insert that t into the equation for y(t). That will give you th3e maximum height.

- calculus -
**john**, Sunday, December 2, 2007 at 8:30pmx = 124..98t; y = 16t^2 + 45.49t + 5

2.729 sec

1.422 sec

4.983 feet

is the answer I'm coming up with ??

- calculus -

**Related Questions**

Physics - A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If ...

Physics - A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If ...

physics - A baseball pitcher can throw a baseball at a speed of 42 m/s. If the ...

physic - a baseball pitcher throws a baseball with a speed of 4m/s.Estimate the ...

college - A baseball pitcher throws a baseball with a speed of 38 . In throwing ...

physics help ! - a baseball pitcher throws a baseball with a speed of 38m/s. ...

h.s physics - a baseball pitcher throws a baseball with a speed of 38m/s. ...

h.s. physics - a baseball pitcher throws a baseball with a speed of 38m/s. ...

Physics - Now assume that the pitcher in Part D throws a 0.145-kg baseball ...

math - Baseball Nick throws a baseball upward with an initial velocity of 60 ...