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September 16, 2014

September 16, 2014

Posted by **Amelie** on Sunday, December 2, 2007 at 4:37pm.

-x^3+2x^2+4x-8

-x^3-5x^2+20x+12

I don't know how to begin. I thought long division, but what would I divide by?

- Math: Factoring -
**drwls**, Sunday, December 2, 2007 at 5:03pmFirst find one root by trial and error. Call it a. Then divide (x-a) into the cubic using long division to get a quadratic equation. Get the roots of that by the usual method.

For the equation

-x^3+2x^2+4x-8,

one of the roots is x=2. Divide (x-2) into -x^3+2x^2+4x-8, and you get

-x^2 + 4 = (4-2)(x+2)

That completes the factoring.

-x^3+2x^2+4x-8 = (x-2)(x+2)(2-x)

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