Wednesday

April 16, 2014

April 16, 2014

Posted by **Krissy** on Sunday, December 2, 2007 at 2:25pm.

1) Passes through (2,3) & (0,-9)

2) Perpendiculat to the line 4x-2x=7 and through (1,-3)

3) Perpendicular to the segments with endpoints (2,1) & (-4,-1) and through the midpoint of the segment.

If possible show some quick work (not the full process)

thank you!!

- Algebra -
**Reiny**, Sunday, December 2, 2007 at 6:02pm1. slope = (3+9)/2-0) = 6

so (y-3)/(x-2)=6

cross-multiply, rearrange for a suitable version of the equation

2. slope of give line = 2, so slope of new line is -1/2

then (y+3)/(x-1) = -1/2

cross-multiply, rearrange for a suitable version of the equation

3. midpoint of segment = ((2-4)/2,(1-1)/2) = (-1,0)

slope of given segment = 1/3

so slope of new line = -3

so (y-0)/(x+1) = -3

cross-multiply, rearrange for a suitable version of the equation

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