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trig

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solve this equation:

4x^3-4x^2+13x-6=0

note: that's suppose to be 4x to the third and 4x squared

  • trig -

    After several tries I found a factor

    (2x-1)(2x^2 - x + 6) = 0
    x = 1/2 or x = (1 ±√-47)/4 or (1 ±i√47)/4

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