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Posted by on Friday, November 30, 2007 at 4:09pm.

A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the train is moving at 59.7 km/hr, in how short a distance can the train be stopped with a constant acceleration without causing the crates to slide?

I have noo idea how to do this. Can someone show me the steps?

  • Physics - , Friday, November 30, 2007 at 6:20pm

    friction between the crates and floor

    Force= mu*mass*g

    But that must equal ma, or m (v^2/(2d))

    mu*mass*g= mass*v^2/2d and you are looking for d.

  • Physics - , Friday, November 30, 2007 at 7:23pm

    How do I find the mass?

  • Physics - , Saturday, December 1, 2007 at 9:31am

    A railroad flatcar is loaded with crates. The coefficient of static friction between the crates and the floor is 0.27. If the train is moving at 59.7 km/hr, in how short a distance can the train be stopped with a constant acceleration without causing the crates to slide?

    Ok so I understand that mu*mass*g= mass*v^2/2d, and I need to solve for d. But how do I get the mass?

  • Physics - , Thursday, September 30, 2010 at 11:24pm

    the masses cancel

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