Joan has one more than 3 times as many cassette tapes as Paul has. Together

they have 25 tapes. How many tapes does Paul have?
ANS: 6 tapes

The answer is 6 tapes. Does anyone know how to do this problem?

To solve this problem, we can set up a system of equations. Let's use P to represent the number of cassette tapes that Paul has and J to represent the number of cassette tapes that Joan has.

According to the problem statement, Joan has one more than 3 times as many cassette tapes as Paul has. So, we can write the equation:
J = 3P + 1

We also know that together they have 25 tapes. So, we can write the equation:
J + P = 25

Now, we can solve this system of equations to find the number of tapes that Paul has.

Substituting the value of J from the first equation into the second equation, we get:
(3P + 1) + P = 25

Simplifying this equation, we get:
4P + 1 = 25

Subtracting 1 from both sides, we get:
4P = 24

Dividing both sides by 4, we get:
P = 6

So, Paul has 6 tapes.

J-1=3P

J+P=25