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December 19, 2014

December 19, 2014

Posted by **Anonymous** on Wednesday, November 28, 2007 at 10:02pm.

2 + 1/7 [x - (x+6 / 7) - 2]

This is what I have:

= 2 + 1/7 ( x -x-6/7 -2)

= 2 + (x - x - 6 - 2 / 49)

= (98 + x - x - 6 - 2) / 49

= 90/49

But the answer is:

6x + 78 / 49

- How do you properly distribute? -
**Reiny**, Wednesday, November 28, 2007 at 11:04pmI believe you meant to type:

2 + 1/7 [x - (x+6)/7 - 2]

= 2 + 1/7[(7x - x - 6 - 14)/7]

= 2 + 1/7[(6x - 20)/7]

= 2 + [(6x - 20)/49]

= 98/49 + (6x - 20)/49

= (98 + 6x - 20)/49

= (6x + 78)/49

watch how you place your brackets, it is extremely important

- How do you properly distribute? -
**Anonymous**, Wednesday, November 28, 2007 at 11:18pm= 2 + 1/7[(7x - x - 6 - 14)/7]

Can you explain how you distributed this part thoroughly?

- How do you properly distribute? -
**Anonymous**, Wednesday, November 28, 2007 at 11:21pmNevermind I got it

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