Posted by **Cat** on Tuesday, November 27, 2007 at 2:48pm.

f(x) = (ax+b)/(x^2 - c)

i) the graph of f is symmetric about the y-axis

ii) limit as x approaches 2+ of f(x) is positive infinity

iii) f'(1) = -2

Determine the values of a, b, c

I got that c = 4 from the first i). I'm stuck on the second one because

f(x) = f(-x)

(ax+b)/(x^2 - c) = (-ax+b)/(x^2 - c)

ax+b = -ax+b

1=-1 ????

## Answer this Question

## Related Questions

- calculus - What is the limit of the function as x approaches infinity? 4x^4 - 4^...
- Calculus - What is the limit of this function as x approaches 0? cos(x) - 1 / x ...
- Calculus - Find limit as x approaches 1 5/(x-1)^2 A. 0 B. Negative infinity C. 5...
- Calculous - Describe in words the long run behavior as x approaches infinity of ...
- Calculus - Determine the behavior of limits A. Limit as x approaches 1 of: (log...
- calculus - evaluate the limit as x approaches positive and negative infinity (x^...
- calculus - what is the answer for the integral of (1/(xln(x)) from 1 to infinity...
- math - With regards to question J: The variables x and y are connected by the ...
- Pre-Calculus-check answers - The graph of the equation y=x^3-x is symmetric with...
- calculus - if i define the function f(x)= x^3-x^2-3x-1 and h(x) = f(x)/g(x), ...