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July 30, 2014

July 30, 2014

Posted by **Cat** on Tuesday, November 27, 2007 at 2:48pm.

i) the graph of f is symmetric about the y-axis

ii) limit as x approaches 2+ of f(x) is positive infinity

iii) f'(1) = -2

Determine the values of a, b, c

I got that c = 4 from the first i). I'm stuck on the second one because

f(x) = f(-x)

(ax+b)/(x^2 - c) = (-ax+b)/(x^2 - c)

ax+b = -ax+b

1=-1 ????

- Calculus -
**bobpursley**, Tuesday, November 27, 2007 at 4:17pmIf it is symettric, then a has to be zero. If a is not zero, then it is an odd function. a being zero satisfies your solution.

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