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July 29, 2014

July 29, 2014

Posted by **Shawna** on Tuesday, November 27, 2007 at 11:45am.

- Algebra 2 -
**bobpursley**, Tuesday, November 27, 2007 at 12:36pmwell, the points give you the opposite side, and the adjacent side. The hypotenuse must then be sqrt (25+16). So now one knows all three sides.

Use the formulas for sine, cosine, and tangent, then invert them for the other three.

- Algebra 2 -
**bobpursley**, Tuesday, November 27, 2007 at 12:36pmwell, the points give you the opposite side, and the adjacent side. The hypotenuse must then be sqrt (25+16). So now one knows all three sides.

Use the formulas for sine, cosine, and tangent, then invert them for the other three.

- Algebra 2 -
**Shawna**, Tuesday, November 27, 2007 at 12:47pmso R would be sqrt41 and then sin=-4/sqrt41 cos=-5/sqrt41 and so on and so forth right?

- Algebra 2 -
- Algebra 2 -
**Nico**, Sunday, January 27, 2008 at 11:16pmThe values of the six trig. functions should be:

sin(theta) = -4

-------

sqrt(41)

cos(theta) = -5

-------

sqrt(41)

tang(theta) = 4/5

csc(theta = sqrt(41)

--------

-4

sec(theta) = sqrt(41)

--------

-5

cot(theta)= 5/4

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